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0.4x^2+1.6x-66=0
a = 0.4; b = 1.6; c = -66;
Δ = b2-4ac
Δ = 1.62-4·0.4·(-66)
Δ = 108.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{108.16}}{2*0.4}=\frac{-1.6-\sqrt{108.16}}{0.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{108.16}}{2*0.4}=\frac{-1.6+\sqrt{108.16}}{0.8} $
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